20y^2+3y+10=

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Solution for 20y^2+3y+10= equation:


Simplifying
20y2 + 3y + 10 = 0

Reorder the terms:
10 + 3y + 20y2 = 0

Solving
10 + 3y + 20y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
20 the coefficient of the squared term: 

Divide each side by '20'.
0.5 + 0.15y + y2 = 0

Move the constant term to the right:

Add '-0.5' to each side of the equation.
0.5 + 0.15y + -0.5 + y2 = 0 + -0.5

Reorder the terms:
0.5 + -0.5 + 0.15y + y2 = 0 + -0.5

Combine like terms: 0.5 + -0.5 = 0.0
0.0 + 0.15y + y2 = 0 + -0.5
0.15y + y2 = 0 + -0.5

Combine like terms: 0 + -0.5 = -0.5
0.15y + y2 = -0.5

The y term is 0.15y.  Take half its coefficient (0.075).
Square it (0.005625) and add it to both sides.

Add '0.005625' to each side of the equation.
0.15y + 0.005625 + y2 = -0.5 + 0.005625

Reorder the terms:
0.005625 + 0.15y + y2 = -0.5 + 0.005625

Combine like terms: -0.5 + 0.005625 = -0.494375
0.005625 + 0.15y + y2 = -0.494375

Factor a perfect square on the left side:
(y + 0.075)(y + 0.075) = -0.494375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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